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| Find the Numbers 3 | |||||
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Using the digits 1,
2, 3, 4, 5, 6, 7, 8 and 9 (each exactly once), can you find
three 3-digits numbers (like 475) so that... The second number is two times the first... and the third number is three times the first? (Just figuring out what this question is asking is going to take some thinking!) There are three solutions... Can you find one of them? All of them?
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